The flight distance from Lanzarote Airport (ACE) in Lanzarote Island, Spain to Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India is 9,895 kilometers (6,148 miles / 5,343 nautical miles). The estimated flight time for this route is approximately 13h, flying east northeast at a heading of 65°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting Spain with India. It is an intercontinental flight between Europe and Asia. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 08:25 in Lanzarote Island, it's 13:55 in Kolkata. The 5.5-hour time difference may cause some jet lag. Most travelers adjust within a day or two.

The return flight from Kolkata (CCU) to Lanzarote Island (ACE) follows a heading of 301° (west northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Lanzarote Airport (ACE) and Netaji Subhash Chandra Bose International Airport (CCU) detail pages, or use our flight duration calculator to compare other routes.