ADR
Andrews
United States
672 km
418 miles
TPA
Tampa
United States
Distance
672 km
418 mi / 363 nm
Est. Flight Time
2h
Short-haul route
Time Difference
+0h
America/New_York
Heading
206°
south southwest

Airport Comparison

ADR TPA
Airport Name Robert F Swinnie Airport Tampa International Airport
IATA Code ADR TPA
ICAO Code KPHH KTPA
City Andrews Tampa
Country United States United States
Timezone America/New_York America/New_York
Elevation 26 ft 26 ft
Coordinates 33.450000, -79.530000 27.980000, -82.530000

Andrews (ADR) to Tampa (TPA) Flight Distance

The flight distance from Robert F Swinnie Airport (ADR) in Andrews, United States to Tampa International Airport (TPA) in Tampa, United States is 672 kilometers (418 miles / 363 nautical miles). The estimated flight time for this route is approximately 2h, flying south southwest at a heading of 206°.

This is a short-haul route typically served by narrow-body aircraft such as the Boeing 737 or Airbus A320 family. In-flight service is usually limited to drinks and light snacks.

This is a domestic route within United States. Both airports operate in the same country, which may simplify travel requirements and documentation.

Time zone information: When it's 00:40 in Andrews, it's 00:40 in Tampa.

The return flight from Tampa (TPA) to Andrews (ADR) follows a heading of 24° (north northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Robert F Swinnie Airport (ADR) and Tampa International Airport (TPA) detail pages, or use our flight duration calculator to compare other routes.

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