ALX
Alexander City
United States
1,382 km
859 miles
JFK
New York
United States
Distance
1,382 km
859 mi / 746 nm
Est. Flight Time
3h
Short-haul route
Time Difference
+1h
America/Chicago
Heading
48°
northeast

Airport Comparison

ALX JFK
Airport Name Thomas C Russell Field John F Kennedy International Airport
IATA Code ALX JFK
ICAO Code KALX KJFK
City Alexander City New York
Country United States United States
Timezone America/Chicago America/New_York
Elevation 686 ft 13 ft
Coordinates 32.910000, -85.960000 40.640000, -73.780000

Alexander City (ALX) to New York (JFK) Flight Distance

The flight distance from Thomas C Russell Field (ALX) in Alexander City, United States to John F Kennedy International Airport (JFK) in New York, United States is 1,382 kilometers (859 miles / 746 nautical miles). The estimated flight time for this route is approximately 3h, flying northeast at a heading of 48°.

This is a short-haul route typically served by narrow-body aircraft such as the Boeing 737 or Airbus A320 family. In-flight service is usually limited to drinks and light snacks.

This is a domestic route within United States. Both airports operate in the same country, which may simplify travel requirements and documentation. Despite being a domestic route, there is a 1-hour time difference between the two cities.

Time zone information: When it's 02:52 in Alexander City, it's 03:52 in New York.

The return flight from New York (JFK) to Alexander City (ALX) follows a heading of 235° (southwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Thomas C Russell Field (ALX) and John F Kennedy International Airport (JFK) detail pages, or use our flight duration calculator to compare other routes.

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