AUS
Austin
United States
2,904 km
1,805 miles
ZPO
Pinehouse Lake
Canada
Distance
2,904 km
1,805 mi / 1,568 nm
Est. Flight Time
4h
Medium-haul route
Time Difference
+0h
America/Chicago
Heading
349°
north northwest

Airport Comparison

AUS ZPO
Airport Name Austin-Bergstrom International Airport Pinehouse Lake Airport
IATA Code AUS ZPO
ICAO Code KAUS CZPO
City Austin Pinehouse Lake
Country United States Canada
Timezone America/Chicago America/Regina
Elevation 542 ft 1,278 ft
Coordinates 30.190000, -97.670000 55.530000, -106.580000

Austin (AUS) to Pinehouse Lake (ZPO) Flight Distance

The flight distance from Austin-Bergstrom International Airport (AUS) in Austin, United States to Pinehouse Lake Airport (ZPO) in Pinehouse Lake, Canada is 2,904 kilometers (1,805 miles / 1,568 nautical miles). The estimated flight time for this route is approximately 4h, flying north northwest at a heading of 349°.

This is a medium-haul route that may be operated by either narrow-body or wide-body aircraft depending on demand. Passengers can expect a meal service on most carriers.

This is an international route connecting United States with Canada. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 15:06 in Austin, it's 15:06 in Pinehouse Lake.

The return flight from Pinehouse Lake (ZPO) to Austin (AUS) follows a heading of 162° (south southeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Austin-Bergstrom International Airport (AUS) and Pinehouse Lake Airport (ZPO) detail pages, or use our flight duration calculator to compare other routes.

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