The flight distance from Virginia Tech/Montgomery Executive Airport (BCB) in Blacksburg, United States to Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India is 13,258 kilometers (8,238 miles / 7,159 nautical miles). The estimated flight time for this route is approximately 17h, flying north northeast at a heading of 12°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting United States with India. It is an intercontinental flight between North America and Asia. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 17:04 in Blacksburg, it's 03:34 in Kolkata. With a 10.5-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 2,104 feet between the two airports. Netaji Subhash Chandra Bose International Airport sits lower than Virginia Tech/Montgomery Executive Airport.

The return flight from Kolkata (CCU) to Blacksburg (BCB) follows a heading of 350° (north). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Virginia Tech/Montgomery Executive Airport (BCB) and Netaji Subhash Chandra Bose International Airport (CCU) detail pages, or use our flight duration calculator to compare other routes.