The flight distance from Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India to Chateauroux-Deols Marcel Dassault Airport (CHR) in Chateauroux/Deols, France is 7,952 kilometers (4,941 miles / 4,294 nautical miles). The estimated flight time for this route is approximately 10h, flying northwest at a heading of 314°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting India with France. It is an intercontinental flight between Asia and Europe. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 14:08 in Kolkata, it's 09:38 in Chateauroux/Deols. The 4.5-hour time difference may cause some jet lag. Most travelers adjust within a day or two.

The return flight from Chateauroux/Deols (CHR) to Kolkata (CCU) follows a heading of 76° (east northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Netaji Subhash Chandra Bose International Airport (CCU) and Chateauroux-Deols Marcel Dassault Airport (CHR) detail pages, or use our flight duration calculator to compare other routes.