CCU
Kolkata
India
4,035 km
2,507 miles
DPL
Dipolog City
Philippines
Distance
4,035 km
2,507 mi / 2,179 nm
Est. Flight Time
6h
Long-haul route
Time Difference
+2.5h
Asia/Kolkata
Heading
107°
east southeast

Airport Comparison

CCU DPL
Airport Name Netaji Subhash Chandra Bose International Airport Dipolog Airport
IATA Code CCU DPL
ICAO Code VECC RPMG
City Kolkata Dipolog City
Country India Philippines
Timezone Asia/Kolkata Asia/Manila
Elevation 16 ft 12 ft
Coordinates 22.650000, 88.450000 8.600000, 123.340000

Kolkata (CCU) to Dipolog City (DPL) Flight Distance

The flight distance from Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India to Dipolog Airport (DPL) in Dipolog City, Philippines is 4,035 kilometers (2,507 miles / 2,179 nautical miles). The estimated flight time for this route is approximately 6h, flying east southeast at a heading of 107°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting India with Philippines. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 00:45 in Kolkata, it's 03:15 in Dipolog City.

The return flight from Dipolog City (DPL) to Kolkata (CCU) follows a heading of 297° (west northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Netaji Subhash Chandra Bose International Airport (CCU) and Dipolog Airport (DPL) detail pages, or use our flight duration calculator to compare other routes.

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