CCU
Kolkata
India
4,086 km
2,539 miles
PAG
Pagadian City
Philippines
Distance
4,086 km
2,539 mi / 2,206 nm
Est. Flight Time
6h
Long-haul route
Time Difference
+2.5h
Asia/Kolkata
Heading
108°
east southeast

Airport Comparison

CCU PAG
Airport Name Netaji Subhash Chandra Bose International Airport Pagadian Airport
IATA Code CCU PAG
ICAO Code VECC RPMP
City Kolkata Pagadian City
Country India Philippines
Timezone Asia/Kolkata Asia/Manila
Elevation 16 ft 5 ft
Coordinates 22.650000, 88.450000 7.830000, 123.460000

Kolkata (CCU) to Pagadian City (PAG) Flight Distance

The flight distance from Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India to Pagadian Airport (PAG) in Pagadian City, Philippines is 4,086 kilometers (2,539 miles / 2,206 nautical miles). The estimated flight time for this route is approximately 6h, flying east southeast at a heading of 108°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting India with Philippines. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 22:51 in Kolkata, it's 01:21 in Pagadian City.

The return flight from Pagadian City (PAG) to Kolkata (CCU) follows a heading of 298° (west northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Netaji Subhash Chandra Bose International Airport (CCU) and Pagadian Airport (PAG) detail pages, or use our flight duration calculator to compare other routes.

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