The flight distance from Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India to Mid-State Airport (PSB) in Philipsburg, United States is 12,815 kilometers (7,963 miles / 6,920 nautical miles). The estimated flight time for this route is approximately 16h, flying north at a heading of 349°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting India with United States. It is an intercontinental flight between Asia and North America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 23:29 in Kolkata, it's 12:59 in Philipsburg. With a 10.5-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 1,932 feet between the two airports. Mid-State Airport sits higher than Netaji Subhash Chandra Bose International Airport.

The return flight from Philipsburg (PSB) to Kolkata (CCU) follows a heading of 14° (north northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Netaji Subhash Chandra Bose International Airport (CCU) and Mid-State Airport (PSB) detail pages, or use our flight duration calculator to compare other routes.