CCU
Kolkata
India
6,433 km
3,997 miles
RZE
Rzeszow
Poland
Distance
6,433 km
3,997 mi / 3,473 nm
Est. Flight Time
9h
Long-haul route
Time Difference
-4.5h
Asia/Kolkata
Heading
316°
northwest

Airport Comparison

CCU RZE
Airport Name Netaji Subhash Chandra Bose International Airport Rzeszow-Jasionka Airport
IATA Code CCU RZE
ICAO Code VECC EPRZ
City Kolkata Rzeszow
Country India Poland
Timezone Asia/Kolkata Europe/Warsaw
Elevation 16 ft 675 ft
Coordinates 22.650000, 88.450000 50.110000, 22.020000

Kolkata (CCU) to Rzeszow (RZE) Flight Distance

The flight distance from Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India to Rzeszow-Jasionka Airport (RZE) in Rzeszow, Poland is 6,433 kilometers (3,997 miles / 3,473 nautical miles). The estimated flight time for this route is approximately 9h, flying northwest at a heading of 316°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting India with Poland. It is an intercontinental flight between Asia and Europe. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 13:37 in Kolkata, it's 09:07 in Rzeszow. The 4.5-hour time difference may cause some jet lag. Most travelers adjust within a day or two.

The return flight from Rzeszow (RZE) to Kolkata (CCU) follows a heading of 92° (east). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Netaji Subhash Chandra Bose International Airport (CCU) and Rzeszow-Jasionka Airport (RZE) detail pages, or use our flight duration calculator to compare other routes.

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