The flight distance from Ioannis Kapodistrias International Airport (CFU) in Kerkyra Island, Greece to O. R. Tambo International Airport (JNB) in Johannesburg, South Africa is 7,360 kilometers (4,573 miles / 3,974 nautical miles). The estimated flight time for this route is approximately 10h, flying south at a heading of 172°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting Greece with South Africa. It is an intercontinental flight between Europe and Africa. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 13:11 in Kerkyra Island, it's 13:11 in Johannesburg.

There is a significant elevation difference of 5,552 feet between the two airports. O. R. Tambo International Airport sits higher than Ioannis Kapodistrias International Airport. Travelers arriving at the higher-elevation airport should be aware of potential altitude effects.

The return flight from Johannesburg (JNB) to Kerkyra Island (CFU) follows a heading of 353° (north). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Ioannis Kapodistrias International Airport (CFU) and O. R. Tambo International Airport (JNB) detail pages, or use our flight duration calculator to compare other routes.