The flight distance from Rajiv Gandhi International Airport Shamshabad (HYD) in Hyderabad, India to Rennell/Tingoa Airport (RNL) in Rennell Island, Solomon Islands is 9,516 kilometers (5,913 miles / 5,138 nautical miles). The estimated flight time for this route is approximately 12h, flying east southeast at a heading of 104°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting India with Solomon Islands. It is an intercontinental flight between Asia and Oceania. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 20:51 in Hyderabad, it's 02:21 in Rennell Island. The 5.5-hour time difference may cause some jet lag. Most travelers adjust within a day or two.

There is a significant elevation difference of 2,024 feet between the two airports. Rennell/Tingoa Airport sits lower than Rajiv Gandhi International Airport Shamshabad.

The return flight from Rennell Island (RNL) to Hyderabad (HYD) follows a heading of 289° (west northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Rajiv Gandhi International Airport Shamshabad (HYD) and Rennell/Tingoa Airport (RNL) detail pages, or use our flight duration calculator to compare other routes.