The flight distance from Pathankot Air Force Station (IXP) in Pathankot Air Force Station, India to John F Kennedy International Airport (JFK) in New York, United States is 11,324 kilometers (7,037 miles / 6,115 nautical miles). The estimated flight time for this route is approximately 14h, flying north northwest at a heading of 337°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting India with United States. It is an intercontinental flight between Asia and North America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 15:52 in Pathankot Air Force Station, it's 05:22 in New York. With a 10.5-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 1,004 feet between the two airports. John F Kennedy International Airport sits lower than Pathankot Air Force Station.

The return flight from New York (JFK) to Pathankot Air Force Station (IXP) follows a heading of 26° (north northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Pathankot Air Force Station (IXP) and John F Kennedy International Airport (JFK) detail pages, or use our flight duration calculator to compare other routes.