Airport Comparison
| JFK | SJT | |
|---|---|---|
| Airport Name | John F Kennedy International Airport | San Angelo Regional/Mathis Field |
| IATA Code | JFK | SJT |
| ICAO Code | KJFK | KSJT |
| City | New York | San Angelo |
| Country | United States | United States |
| Timezone | America/New_York | America/Chicago |
| Elevation | 13 ft | 1,919 ft |
| Coordinates | 40.640000, -73.780000 | 31.360000, -100.500000 |
New York (JFK) to San Angelo (SJT) Flight Distance
The flight distance from John F Kennedy International Airport (JFK) in New York, United States to San Angelo Regional/Mathis Field (SJT) in San Angelo, United States is 2,603 kilometers (1,617 miles / 1,405 nautical miles). The estimated flight time for this route is approximately 4h, flying west southwest at a heading of 255°.
This is a medium-haul route that may be operated by either narrow-body or wide-body aircraft depending on demand. Passengers can expect a meal service on most carriers.
This is a domestic route within United States. Both airports operate in the same country, which may simplify travel requirements and documentation. Despite being a domestic route, there is a 1-hour time difference between the two cities.
Time zone information: When it's 03:50 in New York, it's 02:50 in San Angelo.
There is a significant elevation difference of 1,906 feet between the two airports. San Angelo Regional/Mathis Field sits higher than John F Kennedy International Airport.
The return flight from San Angelo (SJT) to New York (JFK) follows a heading of 59° (east northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.
For more information about these airports, visit the John F Kennedy International Airport (JFK) and San Angelo Regional/Mathis Field (SJT) detail pages, or use our flight duration calculator to compare other routes.