The flight distance from John F Kennedy International Airport (JFK) in New York, United States to Sioux Lookout Airport (YXL) in Sioux Lookout, Canada is 1,757 kilometers (1,092 miles / 949 nautical miles). The estimated flight time for this route is approximately 3h, flying northwest at a heading of 313°.

This is a medium-haul route that may be operated by either narrow-body or wide-body aircraft depending on demand. Passengers can expect a meal service on most carriers.

This is an international route connecting United States with Canada. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 11:04 in New York, it's 10:04 in Sioux Lookout.

There is a significant elevation difference of 1,245 feet between the two airports. Sioux Lookout Airport sits higher than John F Kennedy International Airport.

The return flight from Sioux Lookout (YXL) to New York (JFK) follows a heading of 120° (east southeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the John F Kennedy International Airport (JFK) and Sioux Lookout Airport (YXL) detail pages, or use our flight duration calculator to compare other routes.