The flight distance from O. R. Tambo International Airport (JNB) in Johannesburg, South Africa to Tyndall Afb Airport (PAM) in Panama City, United States is 13,599 kilometers (8,450 miles / 7,343 nautical miles). The estimated flight time for this route is approximately 17h, flying west northwest at a heading of 290°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting South Africa with United States. It is an intercontinental flight between Africa and North America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 21:35 in Johannesburg, it's 14:35 in Panama City. With a 7-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 5,541 feet between the two airports. Tyndall Afb Airport sits lower than O. R. Tambo International Airport. Travelers arriving at the higher-elevation airport should be aware of potential altitude effects.

The return flight from Panama City (PAM) to Johannesburg (JNB) follows a heading of 104° (east southeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the O. R. Tambo International Airport (JNB) and Tyndall Afb Airport (PAM) detail pages, or use our flight duration calculator to compare other routes.