The flight distance from Sir Seewoosagur Ramgoolam International Airport (MRU) in Port Louis, Mauritius to Columbus Municipal Airport (OLU) in Columbus, United States is 16,701 kilometers (10,378 miles / 9,018 nautical miles). The estimated flight time for this route is approximately 21h, flying northwest at a heading of 320°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting Mauritius with United States. It is an intercontinental flight between Africa and North America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 16:19 in Port Louis, it's 07:19 in Columbus. With a 9-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 1,261 feet between the two airports. Columbus Municipal Airport sits higher than Sir Seewoosagur Ramgoolam International Airport.

The return flight from Columbus (OLU) to Port Louis (MRU) follows a heading of 53° (northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Sir Seewoosagur Ramgoolam International Airport (MRU) and Columbus Municipal Airport (OLU) detail pages, or use our flight duration calculator to compare other routes.