The flight distance from Penn Valley Airport (SEG) in Selinsgrove, United States to Warsaw Chopin Airport (WAW) in Warsaw, Poland is 7,012 kilometers (4,357 miles / 3,786 nautical miles). The estimated flight time for this route is approximately 9h, flying northeast at a heading of 43°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting United States with Poland. It is an intercontinental flight between North America and Europe. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 13:10 in Selinsgrove, it's 19:10 in Warsaw. With a 6-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

The return flight from Warsaw (WAW) to Selinsgrove (SEG) follows a heading of 303° (west northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Penn Valley Airport (SEG) and Warsaw Chopin Airport (WAW) detail pages, or use our flight duration calculator to compare other routes.